30x^2-912x+6912=0

Solution for 30x^2-912x+6912=0 equation:

30x^2-912x+6912=0

a = 30; b = -912; c = +6912;
Δ = b2-4ac
Δ = -9122-4·30·6912
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-912)-48}{2*30}=\frac{864}{60}
=14+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-912)+48}{2*30}=\frac{960}{60}
=16
$